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[Python] Render enums as Python IntEnum (#8145)
This allows enums to be type check with mypy. They will still behave like ints -> > IntEnum is the same as Enum, > but its members are also integers and can be used anywhere > that an integer can be used. > If any integer operation is performed with an IntEnum member, > the resulting value loses its enumeration status. https://docs.python.org/3/library/enum.html#enum.IntEnum Only if the --python-typing flag is set.
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@@ -591,12 +591,21 @@ class PythonStubGenerator {
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void GenerateEnumStub(std::stringstream &stub, const EnumDef *enum_def,
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Imports *imports) const {
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stub << "class " << namer_.Type(*enum_def);
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if (version_.major != 3) stub << "(object)";
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if (version_.major == 3){
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imports->Import("enum", "IntEnum");
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stub << "(IntEnum)";
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}
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else {
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stub << "(object)";
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}
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stub << ":\n";
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for (const EnumVal *val : enum_def->Vals()) {
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stub << " " << namer_.Variant(*val) << ": "
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<< ScalarType(enum_def->underlying_type.base_type) << "\n";
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}
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if (parser_.opts.generate_object_based_api & enum_def->is_union) {
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imports->Import("flatbuffers", "table");
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stub << "def " << namer_.Function(*enum_def)
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@@ -2432,7 +2441,7 @@ class PythonGenerator : public BaseGenerator {
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auto field_type = namer_.ObjectType(*ev.union_type.struct_def);
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code +=
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GenIndents(1) + "if unionType == " + union_type + "()." + variant + ":";
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GenIndents(1) + "if unionType == " + union_type + "." + variant + ":";
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if (parser_.opts.include_dependence_headers) {
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auto package_reference = GenPackageReference(ev.union_type);
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code += GenIndents(2) + "import " + package_reference;
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